In above case, Thread- has A but need B to complete processing and Similarly Thread-2 has resource B but need A first.
Let write above scenario in java code:
Let write above scenario in java code:
package thread; public class ResolveDeadLockTest { public static void main(String[] args) { ResolveDeadLockTest test = new ResolveDeadLockTest(); final A a = test.new A(); final B b = test.new B(); // Thread-1 Runnable block1 = new Runnable() { public void run() { synchronized (a) { try { // Adding delay so that both threads can start trying to // lock resources Thread.sleep(100); } catch (InterruptedException e) { e.printStackTrace(); } // Thread-1 have A but need B also synchronized (b) { System.out.println("In block 1"); } } } }; // Thread-2 Runnable block2 = new Runnable() { public void run() { synchronized (b) { // Thread-2 have B but need A also synchronized (a) { System.out.println("In block 2"); } } } }; new Thread(block1).start(); new Thread(block2).start(); } // Resource A private class A { private int i = 10; public int getI() { return i; } public void setI(int i) { this.i = i; } } // Resource B private class B { private int i = 20; public int getI() { return i; } public void setI(int i) { this.i = i; } } }
Running above code will result in deadlock for very obvious reasons (explained above). Now we have to solve this issue.
I believe, solution to any problem lies in identifying the root of problem. In our case, it is the pattern of accessing A and B, is main issue. So, to solve it, we will simply re-order the statements where code is accessing shared resources.
After rewriting the code, it will look like this ::
I believe, solution to any problem lies in identifying the root of problem. In our case, it is the pattern of accessing A and B, is main issue. So, to solve it, we will simply re-order the statements where code is accessing shared resources.
After rewriting the code, it will look like this ::
// Thread-1 Runnable block1 = new Runnable() { public void run() { synchronized (b) { try { // Adding delay so that both threads can start trying to // lock resources Thread.sleep(100); } catch (InterruptedException e) { e.printStackTrace(); } // Thread-1 have A but need B also synchronized (a) { System.out.println("In block 1"); } } } }; // Thread-2 Runnable block2 = new Runnable() { public void run() { synchronized (b) { // Thread-2 have B but need A also synchronized (a) { System.out.println("In block 2"); } } } };Run again above class, and you will not see any deadlock kind of situation. I hope, it will help you in avoiding deadlocks, and if encountered, in resolving them.
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